In this section we will deal with some straight forward but quite useful applications of derivatives. We start with the Rolle’s theorem, a simple but powerful theorem having a lot of practical importance.
(A) ROLLE’S THEOREM
Let
be a function defined on
such that
(i) it is continuous ![[a,b] [a,b]](https://lh3.googleusercontent.com/blogger_img_proxy/AEn0k_sAXIBSOWCWlHo6j0r-lRn-QSt561yp8LJwftGsnV_v5r4tXTGlm1MmKYBcrDiyiWRSduZ3hat-GQyVAdqmqyup-a9OLBFe1oaYRvgUeZgsHpWQQXu5N_ee0KgwhFzoKsFoQtl2RR8=s0-d)
(ii) it is differentiable on 
(iii) 
Then there exists a real number such that
.
The geometrical interpretation of this theorem is quite straightforward. Consider an arbitrary curve
and two points
and
such that
.
Since
and
are joined by a continuous and differentiable curve, at least one point
will always exist in
where the tangent drawn is horizontal, or equivalently,
. Convince yourself that no matter what curve joins
and
, as long as it is continuous and differentiable one such
will always exist.
From Rolle’s theorem, it follows that between any two roots of a polynomial
will lie a root of the polynomial
.
The (straightforward) proof of Rolle’s theorem is left as an exercise to the reader.
(B) LAGRANGE’S MEAN VALUE THEOREM
Let
be a function defined on
such that
(i) it is continuous on ![[a,b] [a,b]](https://lh3.googleusercontent.com/blogger_img_proxy/AEn0k_sAXIBSOWCWlHo6j0r-lRn-QSt561yp8LJwftGsnV_v5r4tXTGlm1MmKYBcrDiyiWRSduZ3hat-GQyVAdqmqyup-a9OLBFe1oaYRvgUeZgsHpWQQXu5N_ee0KgwhFzoKsFoQtl2RR8=s0-d)
(ii) it is differentiable on
.
Then there exists a real number
such that
To interpret this theorem geometrically, we take an arbitrary function
and two arbitrary points
and
on it
We see that no matter what the curve between
and
is like, as long as it is continuous and differentiable, there will exist a
such that the tangent drawn at
will have a slope equal to
i.e, the average slope from
to
.
For a rigorous proof of
, consider the function
Verify that
satisfies all the three criteria of Rolle’s theorem on
so that
or
| |
Notice that
is an extension of the Rolle’s theorem. In fact, for
,
reduces to the Rolle’s theorem.
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