Example: 1 | |
Let be a differentiable function such that
Find a simple expression for .
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Solution: 1 |
Step-1
Differentiating the given relation, we have
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Step-2
This is evidently a first-order linear DE; the IF is . Multiplying it across both sides of the DE renders the DE exact and its solution is given by
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Step-3
From the relation specified in the equation, note that
From , . This gives . Thus, the function has the simple form
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