EDUCATION FOR BETTER TOMMROW
Friday, 8 August 2014
CHAPTER 15-Worked Out Examples 5
In a quadrilateral
is the mid-point of
is a point on
, prove that
Since no position vectors have been specified in the question (only the sides have been specified), there is no loss of generality in assuming that
is the origin
It is known that in a
be any point in the plane of
. Prove the following assertions:
and divides it in the ratio
are collinear and
(Same logic as above)
(again, same as above)
For any arbitrary point
in the plane of
Go over the solution again if you find any part of it confusing.
August 08, 2014
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