Consider a function
that attains a local maximum at
as shown in the figure below:
It is obvious that the tangent drawn to the curve at
must have
slope, i,e,
.
This is therefore a necessary condition; however, it is not sufficient.
Consider 
Observe that even though
is not an extremum point. What is then, the difference between this and the function discussed previously in Fig-
?
In the previous function, observe that
is positive for
and negative for
(we only need to focus on the neighbourhood of
) i.e,
changes sign from positive to negative as
crosses
.
What would have happened had
been a local minimum point?
We now see that
changes sign from negative to positive as
crosses
.
However, for
, observe that
does not change sign as
crosses
;
whether
or
.
This distinction therefore leads us to our sufficient condition.
but
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These straight forward criteria constitute what is known as the First Derivative Test.
The tedious task of evaluating the sign of
in the left hand and right hand side of
can be done away with by using the Second Derivative Test:
What happens if
is also
?
To deal with such a situation , there is finally a Higher Order Derivative Test:
If
and 
If
is even and
otherwise
|
If
is odd
(
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Let us apply this test to some examples:
Notice that the Higher Order Derivative Test that we have applied here is actually nothing but the Second Order Derivative Test.
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These examples should give you an idea on how to apply the higher order derivative test in case it is required.
However, the first and second order derivative tests will suffice for all our requirements.
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